Moles, Stoichiometry & Limiting Reactants — Interactive Study Tool

SCH3U · Unit 2a · Moles · Molar Mass · Stoichiometry · Limiting Reactants · Percent Yield

← All units
The Mole
Avogadro's number — the chemist's counting unit
One mole = 6.02 × 1023 particles
602,000,000,000,000,000,000,000
A mole (mol) is simply a count — like "a dozen" means 12, "a mole" means 6.02 × 10²³. That count is called Avogadro's number (NA). Particles can be atoms, molecules, or formula units — you must always say which.
How big is a mole, really?
Reference—
One mole6.02 × 10²³
A mole is bigger by—
A mole of seconds
If you counted one particle every second, without ever stopping, counting out a single mole would take about 1.9 × 10¹⁶ years — roughly 1.4 million times the current age of the universe. This is why chemists never count particles directly: they weigh them instead.
Atomic Mass & Molar Mass
Weighing one mole of something
Atomic mass
The mass of one mole of atoms of an element, in g/mol. Read it straight off the periodic table.

Fe = 55.8 g/mol  ·  O = 16.0 g/mol  ·  Cl = 35.5 g/mol
Molar mass
The mass of one mole of molecules (or formula units) of a compound, in g/mol. Found by adding up the atomic masses of every atom in the formula.

H₂ = 2(1.01) = 2.02 g/mol
Molar mass calculator
Periodic table lookup
Click an element to add it to the formula box
The Mole Road Map
Three equations — every route passes through moles
Volume ↔ moles
n = V / MV
MV = 22.4 L/mol at STP
Mass ↔ moles
n = m / mm
mm = molar mass (g/mol)
Particles ↔ moles
n = #p / NA
NA = 6.02 × 10²³ /mol
STP = Standard Temperature and Pressure, 0 °C and 1 atmosphere. The molar volume 22.4 L/mol applies to any gas at STP — it does not apply to solids or liquids.
Interactive road map
mm = 32.00 g/mol
Try these (from the slides)
Road map · moles → particles → atoms
Atoms from molecules
Type any formula in the box below — the tool works out moles → molecules → atoms of whichever element you choose, for whatever you enter.
Mole Ratios
The coefficients of a balanced equation
A mole ratio comes straight from the coefficients of a balanced chemical equation. It only works if the equation is balanced — so balance first, always.

How to use it: divide by the coefficient of what you HAVE, multiply by the coefficient of what you WANT.
Mole ratio explorer
Mole ratio:
mol of ?
Stoichiometry Solver
Mole-mole · mole-mass · mass-mass · mixed
Every stoichiometry problem is the same journey: convert what you HAVE into moles → use the mole ratio → convert moles into what you WANT. The quantity must be in moles before you use the mole ratio.
Solver
of
of
Energy Stoichiometry
Treating heat as another species in the equation
Endothermic
Heat ENTERS — it appears on the reactant side, because it is consumed.
A + B + 40.0 kJ → C + D
Exothermic
Heat EXITS — it appears on the product side, because it is released.
E + F → G + H + 120. kJ
Energy calculator
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Reaction typeExothermic
Energy— kJ
DirectionReleased
Limiting Reactants
Whatever runs out first decides how much you can make
The limiting reactant (LR) is the one that gets used up first. It caps how much product can form. Everything else is in excess and some of it will be left over when the reaction stops.
⚠ Careful — a very common trap. The limiting reactant is not simply "the one with the fewest moles". You must divide each reactant's moles by its coefficient first, then take the smallest result.

In CH₄ + 2O₂ → CO₂ + 2H₂O with 2.50 mol CH₄ and 4.80 mol O₂: fewest moles would wrongly say CH₄ — but 2.50 ÷ 1 = 2.50 while 4.80 ÷ 2 = 2.40, so O₂ is actually limiting. Always divide by the coefficient.
🍔 Build a double cheeseburger
Recipe: 1 bun · 1 tomato slice · 1 lettuce leaf · 2 cheese slices · 2 patties
Burgers made0
Limiting ingredient—
Left over—
🚲 Quick check — bicycles
1 frame + 2 wheels → 1 bicycle
2
6
Limiting reactant calculator
Limiting reactant—
In excess—
Product formed—
Excess left over—
Visualising it — 10 H₂ + 7 O₂
2 H₂(g)+ O₂(g)→ 2 H₂O(g)
Initial10 mol7 mol0 mol
Change−10 mol−5 mol+10 mol
Final0 mol2 mol10 mol
H₂ runs out completely — it is the limiting reactant. Two moles of O₂ are left over as excess.
Theoretical, Actual & Percent Yield
Comparing experimental and calculated yields
Theoretical yield — what stoichiometry says you should get. Always calculated.

Actual yield — what you really scraped out of the flask. Always measured.
% yield = actual yield theoretical yield × 100
Actual yield is almost always lower than theoretical — product is lost on filter paper and glassware, reactions run incompletely, and side reactions steal material. A % yield above 100 % usually means the product is still wet or contaminated.
Percent yield calculator
g
g
Percent yield—
Product lost—
Verdict—
Stoichiometry in the Real World
Why chemists count in moles
🏭 The Haber process — industrial stoichiometry
Ammonia for fertiliser is made by N2 + 3H2 → 2NH3. The plant feeds nitrogen and hydrogen in a precise 1 : 3 mole ratio over an iron catalyst. Only about 15 % converts on each pass, so the unreacted gas is separated and recycled — that is how the overall percent yield is pushed close to 100 %.
Where mole ratios, limiting reactants and percent yield show up
Periodic Table
Class-standard table · based on mass of carbon-12 = 12.00
Periodic table of the elements — class-standard version, based on carbon-12 = 12.00
Read atomic masses straight off this table when finding molar masses for the mole road map and the stoichiometry solver.
Ion Chart
Class-standard chart · common cations, anions & polyatomic ions with their charges
Names, formulae, and charges of common ions — positive ions (cations) and negative ions (anions)
Use these charges to write correct formulas before you balance an equation or run a stoichiometry calculation — the subscripts come from making the positive and negative charges cancel.
Quantities Practice Quiz
30 questions · 20 s conceptual / 40 s numerical · Speed bonus scoring
🐹
Ready to test your knowledge?
Covers moles, molar mass, the three mole equations, mole ratios, stoichiometry, energy, limiting reactants & percent yield
30
Questions
20–40s
Per question
1000
Max points
Summary
Quick reference
ConceptEquationNotes
Avogadro's numberNA = 6.02 × 10²³ /molParticles = atoms, molecules or formula units
Volume ↔ molesn = V / MVMV = 22.4 L/mol — gases at STP only
Mass ↔ molesn = m / mmRearranged: m = n × mm
Particles ↔ molesn = #p / NARearranged: #p = n × NA
Mole ratio÷ coefficient of HAVE, × coefficient of WANTRequires a balanced equation
Limiting reactantsmallest of (moles ÷ coefficient)Not simply the fewest moles
Excess left overmoles at start − moles usedMoles used comes from the LR via stoichiometry
Percent yield(actual ÷ theoretical) × 100Theoretical = calculated, actual = measured
Energy: endothermic → heat on the reactant side (absorbed) · exothermic → heat on the product side (released)
Golden rule: the quantity must be in moles before you use the mole ratio.